1.99=x^2-4x+5

Solution for 1.99=x^2-4x+5 equation:

1.99=x^2-4x+5

We move all terms to the left:

1.99-(x^2-4x+5)=0

We get rid of parentheses

-x^2+4x-5+1.99=0

We add all the numbers together, and all the variables

-1x^2+4x-3.01=0

a = -1; b = 4; c = -3.01;
Δ = b2-4ac
Δ = 42-4·(-1)·(-3.01)
Δ = 3.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{3.96}}{2*-1}=\frac{-4-\sqrt{3.96}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{3.96}}{2*-1}=\frac{-4+\sqrt{3.96}}{-2}
$